drivers/net/a2065.c: Convert release_resource to release_region/release_mem_region

Request_mem_region should be used with release_mem_region, not
release_resource.

The semantic match that finds this problem is as follows:
(http://coccinelle.lip6.fr/)

// <smpl>
@@
expression x,E;
@@
*x = request_mem_region(...)
... when != release_mem_region(x)
when != x = E
* release_resource(x);
// </smpl>

Signed-off-by: Julia Lawall <[e-mail]>
Signed-off-by: David S. Miller <[e-mail]>

drivers/net/a2065.c

···
 		return -EBUSY;
 	r2 = request_mem_region(mem_start, A2065_RAM_SIZE, "RAM");
 	if (!r2) {
-		release_resource(r1);
+		release_mem_region(base_addr, sizeof(struct lance_regs));
 		return -EBUSY;
 	}
 
 	dev = alloc_etherdev(sizeof(struct lance_private));
 	if (dev == NULL) {
-		release_resource(r1);
-		release_resource(r2);
+		release_mem_region(base_addr, sizeof(struct lance_regs));
+		release_mem_region(mem_start, A2065_RAM_SIZE);
 		return -ENOMEM;
 	}
 
···
 
 	err = register_netdev(dev);
 	if (err) {
-		release_resource(r1);
-		release_resource(r2);
+		release_mem_region(base_addr, sizeof(struct lance_regs));
+		release_mem_region(mem_start, A2065_RAM_SIZE);
 		free_netdev(dev);
 		return err;
 	}