fanotify: Fix the checks in fanotify_fsid_equal

Clang warns:

fs/notify/fanotify/fanotify.c:28:23: warning: self-comparison always
evaluates to true [-Wtautological-compare]
return fsid1->val[0] == fsid1->val[0] && fsid2->val[1] == fsid2->val[1];
^
fs/notify/fanotify/fanotify.c:28:57: warning: self-comparison always
evaluates to true [-Wtautological-compare]
return fsid1->val[0] == fsid1->val[0] && fsid2->val[1] == fsid2->val[1];
^
2 warnings generated.

The intention was clearly to compare val[0] and val[1] in the two
different fsid structs. Fix it otherwise this function always returns
true.

Fixes: afc894c784c8 ("fanotify: Store fanotify handles differently")
Link: https://github.com/ClangBuiltLinux/linux/issues/952
Link: https://lore.kernel.org/r/[e-mail]
Signed-off-by: Nathan Chancellor <[e-mail]>
Reviewed-by: Nick Desaulniers <[e-mail]>
Signed-off-by: Jan Kara <[e-mail]>

fs/notify/fanotify/fanotify.c

···
 static inline bool fanotify_fsid_equal(__kernel_fsid_t *fsid1,
 				       __kernel_fsid_t *fsid2)
 {
-	return fsid1->val[0] == fsid1->val[0] && fsid2->val[1] == fsid2->val[1];
+	return fsid1->val[0] == fsid2->val[0] && fsid1->val[1] == fsid2->val[1];
 }
 
 static bool fanotify_fh_equal(struct fanotify_fh *fh1,