bpf, i386: Remove unneeded conversion to bool

The '==' expression itself is bool, no need to convert it to bool again.
This fixes the following coccicheck warning:

arch/x86/net/bpf_jit_comp32.c:1478:50-55: WARNING: conversion to bool not needed here
arch/x86/net/bpf_jit_comp32.c:1479:50-55: WARNING: conversion to bool not needed here

Signed-off-by: Jason Yan <[e-mail]>
Signed-off-by: Daniel Borkmann <[e-mail]>
Acked-by: Martin KaFai Lau <[e-mail]>
Link: https://lore.kernel.org/bpf/[e-mail]

arch/x86/net/bpf_jit_comp32.c

···
 	for (i = 0; i < insn_cnt; i++, insn++) {
 		const s32 imm32 = insn->imm;
 		const bool is64 = BPF_CLASS(insn->code) == BPF_ALU64;
-		const bool dstk = insn->dst_reg == BPF_REG_AX ? false : true;
-		const bool sstk = insn->src_reg == BPF_REG_AX ? false : true;
+		const bool dstk = insn->dst_reg != BPF_REG_AX;
+		const bool sstk = insn->src_reg != BPF_REG_AX;
 		const u8 code = insn->code;
 		const u8 *dst = bpf2ia32[insn->dst_reg];
 		const u8 *src = bpf2ia32[insn->src_reg];